3.9 Example 2 percents solutions

Let g = the number of gallons of 100% antifreeze to be added. Make a table.

	gallons	Price
35% solution	2	(.35)(2)
100% solution	g	(1.)(g)
50% solution	2 + g	(.5)(2 + g)

(.35)(2) + (1.)(g) = (.5)(2 + g)

Solve. . .

g = .60

Darryl should add 0.60 gallons of 100%
antifreeze to produce a 50% solution.